3.1.64 \(\int x^4 (a+b x)^3 \, dx\)

Optimal. Leaf size=43 \[ \frac {a^3 x^5}{5}+\frac {1}{2} a^2 b x^6+\frac {3}{7} a b^2 x^7+\frac {b^3 x^8}{8} \]

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Rubi [A]  time = 0.02, antiderivative size = 43, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {43} \begin {gather*} \frac {1}{2} a^2 b x^6+\frac {a^3 x^5}{5}+\frac {3}{7} a b^2 x^7+\frac {b^3 x^8}{8} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^4*(a + b*x)^3,x]

[Out]

(a^3*x^5)/5 + (a^2*b*x^6)/2 + (3*a*b^2*x^7)/7 + (b^3*x^8)/8

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int x^4 (a+b x)^3 \, dx &=\int \left (a^3 x^4+3 a^2 b x^5+3 a b^2 x^6+b^3 x^7\right ) \, dx\\ &=\frac {a^3 x^5}{5}+\frac {1}{2} a^2 b x^6+\frac {3}{7} a b^2 x^7+\frac {b^3 x^8}{8}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 43, normalized size = 1.00 \begin {gather*} \frac {a^3 x^5}{5}+\frac {1}{2} a^2 b x^6+\frac {3}{7} a b^2 x^7+\frac {b^3 x^8}{8} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^4*(a + b*x)^3,x]

[Out]

(a^3*x^5)/5 + (a^2*b*x^6)/2 + (3*a*b^2*x^7)/7 + (b^3*x^8)/8

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^4 (a+b x)^3 \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[x^4*(a + b*x)^3,x]

[Out]

IntegrateAlgebraic[x^4*(a + b*x)^3, x]

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fricas [A]  time = 1.07, size = 35, normalized size = 0.81 \begin {gather*} \frac {1}{8} x^{8} b^{3} + \frac {3}{7} x^{7} b^{2} a + \frac {1}{2} x^{6} b a^{2} + \frac {1}{5} x^{5} a^{3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(b*x+a)^3,x, algorithm="fricas")

[Out]

1/8*x^8*b^3 + 3/7*x^7*b^2*a + 1/2*x^6*b*a^2 + 1/5*x^5*a^3

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giac [A]  time = 1.22, size = 35, normalized size = 0.81 \begin {gather*} \frac {1}{8} \, b^{3} x^{8} + \frac {3}{7} \, a b^{2} x^{7} + \frac {1}{2} \, a^{2} b x^{6} + \frac {1}{5} \, a^{3} x^{5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(b*x+a)^3,x, algorithm="giac")

[Out]

1/8*b^3*x^8 + 3/7*a*b^2*x^7 + 1/2*a^2*b*x^6 + 1/5*a^3*x^5

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maple [A]  time = 0.00, size = 36, normalized size = 0.84 \begin {gather*} \frac {1}{8} b^{3} x^{8}+\frac {3}{7} a \,b^{2} x^{7}+\frac {1}{2} a^{2} b \,x^{6}+\frac {1}{5} a^{3} x^{5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*(b*x+a)^3,x)

[Out]

1/5*a^3*x^5+1/2*a^2*b*x^6+3/7*a*b^2*x^7+1/8*b^3*x^8

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maxima [A]  time = 1.32, size = 35, normalized size = 0.81 \begin {gather*} \frac {1}{8} \, b^{3} x^{8} + \frac {3}{7} \, a b^{2} x^{7} + \frac {1}{2} \, a^{2} b x^{6} + \frac {1}{5} \, a^{3} x^{5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(b*x+a)^3,x, algorithm="maxima")

[Out]

1/8*b^3*x^8 + 3/7*a*b^2*x^7 + 1/2*a^2*b*x^6 + 1/5*a^3*x^5

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mupad [B]  time = 0.04, size = 35, normalized size = 0.81 \begin {gather*} \frac {a^3\,x^5}{5}+\frac {a^2\,b\,x^6}{2}+\frac {3\,a\,b^2\,x^7}{7}+\frac {b^3\,x^8}{8} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*(a + b*x)^3,x)

[Out]

(a^3*x^5)/5 + (b^3*x^8)/8 + (a^2*b*x^6)/2 + (3*a*b^2*x^7)/7

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sympy [A]  time = 0.08, size = 37, normalized size = 0.86 \begin {gather*} \frac {a^{3} x^{5}}{5} + \frac {a^{2} b x^{6}}{2} + \frac {3 a b^{2} x^{7}}{7} + \frac {b^{3} x^{8}}{8} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**4*(b*x+a)**3,x)

[Out]

a**3*x**5/5 + a**2*b*x**6/2 + 3*a*b**2*x**7/7 + b**3*x**8/8

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